[Python] 성격유형 검사하기

2022 KAKAO TECH INTERNSHIP 

성격 유형 검사하기

 

문제링크는 아래

프로그래머스

 

좋다고 생각하는 코드. 

def solution(survey, choices):
    answer=''
    dic = {"R" : 0,"T" : 0,"C" : 0,"F" : 0,"J" : 0,"M" : 0,"A" : 0,"N" : 0}
    
    for s, c in zip(survey, choices):
        if c>4: 
            dic[s[1]] += c-4
        elif c<4: 
            dic[s[0]] += 4-c

	li = list(dic.items())
    
    for i in range(0,8,2): #range(start, stop, step)
        if li[i][1] < li[i+1][1]:
            answer += li[i+1][0]
        else: 
            answer += li[i][0]
    return answer

 

 

 

내가 풀었지만 실패한코드. 참고용으로 저장. 

from collections import Counter
import operator

def solution(survey, choices):
    
    type_list = []
    for i in range(len(survey)):
        t = list(str(survey[i]))
        type_list.append(t)
        
    select_types=[]
    for j in range(len(survey)):
        if choices[j] >= 5:
            select_type = type_list[j][1]
        elif choices[j] <= 3:
            select_type = type_list[j][0]
        else :
            select_type = sorted(type_list[j])[0]
        select_types.append(select_type)   
    
    score_list = []
    for i in choices:
        if i == 5 or i ==3:
            s = 1
        if i == 6 or i ==2:
            s = 2
        if i == 7 or i ==1:
            s = 3 
        score_list.append(str(s))    
    
    #lst = [(select_types[i], score_list[i]) for i in range(len(survey))]
    sub_dic =({'R':0,'T':0,'C':0,'F':0,'J':0,'M':0,'A':0,'N':0}) 
    for i in range(len(survey)): 
        dic = {select_types[i] : int(score_list[i])}
        sub_dic = dict(Counter(dic)+Counter(sub_dic))
        print(sub_dic)
        
    #sorted_dic = sorted(sub_dic.items(), key=operator.itemgetter(1), reverse=True)
    
    total =({'R':0,'T':0,'C':0,'F':0,'J':0,'M':0,'A':0,'N':0}) 
    total.update(sub_dic)
    
    answer=[]
    if total["R"] >= total["T"]:
        answer += "R"
    else: 
        answer += "T" 
    if total["C"] >= total["F"]:
        answer += "C"
    else: 
        answer += "F" 
    if total["J"] >= total["M"]:
        answer += "J"
    else: 
        answer += "M" 
    if total["A"] >= total["N"]:
        answer += "A"
    else: 
        answer += "N" 
    
    answer = ''.join(answer)
    return answer